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6p^2-33p=33p
We move all terms to the left:
6p^2-33p-(33p)=0
We add all the numbers together, and all the variables
6p^2-66p=0
a = 6; b = -66; c = 0;
Δ = b2-4ac
Δ = -662-4·6·0
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-66)-66}{2*6}=\frac{0}{12} =0 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-66)+66}{2*6}=\frac{132}{12} =11 $
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